where $v = 0$ (final velocity), $u = 4$ m/s (initial velocity), $a = -\frac{5}{2}$ m/s$^2$ (acceleration), and $s$ is the displacement.
First, we need to find the displacement of the object. Using the equation of motion, we get: dc pandey physics class 11 pdf download part 1 work
$$v^2 = u^2 + 2as$$
where $W$ is the net work done and $\Delta KE$ is the change in kinetic energy. Let's consider some problems and their solutions: where $v = 0$ (final velocity), $u =
$$s = \frac{u^2}{2a} = \frac{4^2}{2 \cdot \frac{5}{2}} = \frac{16}{5} m$$ where $v = 0$ (final velocity)
A force of 10 N is applied to an object, causing it to move 5 m in the direction of the force. Calculate the work done.